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Permutational Symmetries of One- and Two-Electron Integrals



C. David Sherrill
Department of Chemistry
University of California, Berkeley
September 1996



Most algorithms in ab initio electronic structure theory compute quantities in terms of one- and two-electron integrals. Using the notation of Szabo and Ostlund, Modern Quantum Chemistry, the one-electron integrals over spin orbitals in physicist's notation are defined as

\begin{displaymath}
\langle i \vert h \vert j \rangle = \int d{\mathbf x}_1 \chi...
 ...}({\mathbf x}_1) 
 \hat{h}({\mathbf r}_1) \chi_j({\mathbf x}_1)\end{displaymath} (1)
where the one-electron Hamiltonian operator ${\hat h}({\mathbf r}_1)$ is defined as
\begin{displaymath}
{\hat h}({\mathbf r}_1) = 
 - \frac{1}{2} \nabla_1^2 - \sum_{A} \frac{Z_A}{r_{1A}}\end{displaymath} (2)
It is immediately obvious that
\begin{displaymath}
\langle i \vert h \vert j \rangle = \langle j \vert h \vert i \rangle^*\end{displaymath} (3)
or
\begin{displaymath}[i \vert h \vert j]
= [j \vert h \vert i]^*\end{displaymath} (4)
in chemists' notation, which is equivalent to physicists' notation for one-electron integrals. For real orbitals, then,
\begin{displaymath}
\langle i \vert h \vert j \rangle = \langle j \vert h \vert i \rangle\end{displaymath} (5)
\begin{displaymath}[i \vert h \vert j]
= [j \vert h \vert i]\end{displaymath} (6)
These symmetries are unchanged if the spin is integrated out to yield spatial orbitals.

Permutational symmetries in the two-electron integrals are somewhat more interesting. The two-electron integral in physicists' notation is
\begin{displaymath}
\langle ij \vert kl \rangle =
\int d{\mathbf x}_1 d{\mathbf ...
 ... \frac{1}{r_{12}} 
 \chi_k({\mathbf x}_1) \chi_l({\mathbf x}_2)\end{displaymath} (7)
while in chemists' notation it is written
\begin{displaymath}[ij \vert kl]
=
\int d{\mathbf x}_1 d{\mathbf x}_2 
 \chi_i^{...
 ...ac{1}{r_{12}} 
 \chi_k^{*}({\mathbf x}_2) \chi_l({\mathbf x}_2)\end{displaymath} (8)

Clearly the integral is unchanged if the dummy indices of integration are permuted. This leads to the symmetry
\begin{displaymath}
\langle ij \vert kl \rangle = \langle ji \vert lk \rangle\end{displaymath} (9)
Furthermore, the complex conjugate of the integral is
\begin{displaymath}
\langle ij \vert kl \rangle = \langle kl \vert ij \rangle^*\end{displaymath} (10)
Combining these two symmetries leads to one further equality, namely
\begin{displaymath}
\langle ij \vert kl \rangle = \langle lk \vert ji \rangle^*\end{displaymath} (11)
Therefore, in the general case we have
\begin{displaymath}
\langle ij \vert kl \rangle = \langle ji \vert lk \rangle = \langle kl \vert ij \rangle^* = \langle lk \vert ji \rangle^*\end{displaymath} (12)
or
\begin{displaymath}[ij \vert kl]
= [kl \vert ij] = [ji \vert lk]^* = [lk \vert ji]^*\end{displaymath} (13)

For the case of real orbitals, we can clearly remove the complex conjugations in the equations above, leading to a four-fold permutational symmetry in the two-electron integrals. However, an additional symmetry arises if the orbitals are real: in that case, the same integral is obtained if $i$ and $k$ (or $j$ and $l$)are swapped in $\langle ij \vert kl \rangle$. It is trivial to verify that this leads to an overall eightfold permutational symmetry,

$\displaystyle \langle ij \vert kl \rangle = \langle ji \vert lk \rangle = \langle kl \vert ij \rangle = \langle lk \vert ji \rangle =$      (14)
$\displaystyle \langle kj \vert il \rangle = \langle li \vert jk \rangle = \langle il \vert kj \rangle = \langle jk \vert li \rangle$        

or

$\displaystyle [ij \vert kl] = [kl \vert ij] = [ji \vert lk] = [lk \vert ji] =$      (15)
$\displaystyle [ji \vert kl] = [lk \vert ij] = [ij \vert lk] = [kl \vert ji]$        

Finally, it is worthwhile to consider the permutational symmetries in the antisymmetrized two-electron integral, $\langle ij \vert\vert kl \rangle$,defined as

$\displaystyle \langle ij \vert\vert kl \rangle$ $\textstyle =$ $\displaystyle \langle ij \vert kl \rangle - \langle ij \vert lk \rangle$ (16)
  $\textstyle =$ $\displaystyle [ik \vert jl] - [il \vert jk]$ (17)

In the general case, the permutational symmetries are

$\displaystyle \langle ij \vert\vert kl \rangle = \langle ji \vert\vert lk \rangle = \langle kl \vert\vert ij \rangle^* = \langle lk \vert\vert ji \rangle^* =$      (18)
$\displaystyle -\langle ij \vert\vert lk \rangle = -\langle ji \vert\vert kl \rangle = -\langle lk \vert\vert ij \rangle^* = -\langle kl \vert\vert ji \rangle^*$        

One consequence of these relationships is that
\begin{displaymath}
\langle ii \vert\vert jk \rangle = \langle ij \vert\vert kk \rangle = 0\end{displaymath} (19)


 
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Next: About this document ... Up: Quantum Chemistry Lecture Notes
© 1997 by C. David Sherrill  / sherrill@alum.mit.edu
Last modified: 8/10/1997